An aqueous solution of carbonic acid reacts to reach equilibrium as described below.
H2CO3(aq) + H2O(l) <---> HCO3^-(aq) + H3O^+(aq)
The solution contains the following solute concentrations:
Carbonic Acid: 3.3*10^-2 mol/L
HCO3^-: 1.19*10^-4 mol/L
H3O^+: 1.19*10^-4 mol/L
Determine the Keq
Work:
Keq= (1.19*10^-4)(1.19*10^-4)/3.3*10^-2
Keq=1.4161*10^-8/3.3*10^-2
Keq= 4.29*10^-7
2 answers
Needs a chemist
nevermind figured it out
3 answers