CaCl2 is three particles per molecule.
deltaTemp=1.3=.52*molality
solve for molality, then
molality= moles/1000 solve for moles, then finally,grams of CaCl2 from moles, then divide by 1000 to get kg
An aqueous solution of calcium chloride boils at 101.3. How many kilograms of calcium chloride were dissolved in 1000 g of the solvent?
2 answers
0.0936
1 answer