Really? 1.8C, above the freezing point of water? I bet you mean -1.8C.
-1.8C=-.52*17.5/(molmass*.100)
solve for molmass
an aqueous solution containing 17.5g of an unknown molecular(nonelectrolyte) compound in 100.0g of water has a freezing point of 1.8 degress C. calculate the molar mass of the unknown compound
4 answers
im lost where did you get the 52 from
I think Mr. Pursley typed in the boiling point elevation constant of 0.52 C when he intended to type in 1.86 for the freezing point constant.
not sure where to start. do i use the freezing point depression equation
0 answers