An aqueous antifreeze is 40.0% ethylene glycol (C2H6O2) by mass. The density of the solution is 1.05 g/cm3. Calculate the molality, molarity, and mole fraction of the ethylene glycol.

Answer 1

A long problem here. You can help by telling me what you don't understand about it before I spent half the night working all of it out in detail.
I'll get you started.
40% by mass means 40 g ethylene glycol + 60 g water.
Convert 40 g ethylene glycol to moles. moles = grams/molar mass.
molality = moles/kg solvent(60 g water = 0.060 kg).
For molarity, use mols/L of solution.
Look up mole fraction.
That's X_{eth gly} = (n_{eth gly}/total moles.

Answer 2

6.77M