an antique dealer visited three shops.she spent 25$ at the first shop.at the second shop she spent half of her remaining money .at the third shop she spent one third of her remaining money and had 60$ left.How much money did the dealer have originally?

Question

an antique dealer visited three shops.she spent 25$ at the first shop.at the second shop she spent half of her remaining money .at the third shop she spent one third of her remaining money  and had 60$ left.How much money did the dealer have originally?

PsyDAG · Answer

Let x = original money x - 25 - .5(x-25) - [.5(x-25)]/3 = 60 Solve for x.

Henry · Answer

Original Amt. = $X.

1. Spent: $25.
Bal. = (X-25).

2. Spent: (X-25)/2.
Bal. = (X-25)/2.

3. Spent: (1/3)(X-25)/2 = (x-25)/6.
Bal. = (X-25)/2 - (x-25)/6,
Bal.=3(X-25)/6 - (X-25)/6 = 2(X-25)/6 =
(X-25)/3.

Bal. = (X-25)/3 = $60.
(X-25)/3 = 60,
Multiply both sides by 3:
X - 25 = 180,
X = 180 + 25 = $205. = Original Amt.