an antelope moving with constant acceleration covers the distance between two points that are 80 meters apart in 7 seconds. Its velocity as it passes the second point is 15 meters per second.

Question

What is the antelope's velocity at the first point?

What is the acceleration ?

Answer 1

say x = 0 at start, t = 0
x = 80 at t = 7
v = 15 at x = 80 and t = 7

v = Vo + a t

x = 0 + Vo t + .5 a t^2

so
15 = Vo + 7 a
80 = Vo (7) +.5 a (49)
solve those two equations for Vo and a

Answer 2

could you explain simpler . i get condfused easily im in 10th grade taking 12 grade classes its tough. any help will do

Answer 3

ok, you have 2 equations in your physics book for constant acceleration

velocity = initial velocity + acceleration times time
or
v = Vo + a t

position = initial position + initial velocity times time + half of acceleration times time squared
or
x = Xo + Vo t +(1/2) a t^2

here I called Xo, initial position zero and x after 7 seconds was 80
so
80 = 0 + Vo (7) + (1/2) a (7)^2

and I know final velocity at t = 7 is 15 but I do not know Vo
so
15 = Vo + a (7)

Answer 4

Obviously, you're in over your head. Maybe you should be taking 10th grade classes.

Answer 5

They may have used different letters and so forth, but the equations are there in the book I am sure.

Answer 6

ashley got the function stuff ok and we will get this as well.

Answer 7

i know this . im doing well i just need a little help

Answer 8

thank you damon. i know we will

Answer 9

not me