An ant climbs onto the side of a bicycle tire a distance of 40.0 m from the hub. If the 0.010 g ant can hold onto the tire with a force of 4.34*10 to the -4, at what frequency would the tire fling the ant of assuming the wheel is spun on a horizontal plane?

Question

An ant climbs onto the side of a bicycle tire a distance of 40.0 m from the hub. If the 0.010 g ant can hold onto the tire with a force of 4.34*10 to the -4, at what frequency would the tire fling the ant of assuming the wheel is spun on a horizontal plane?
so what I did for this question was!!
I used the formula for Force centripetal, and substituted everything and solved for T which is the "frequency". But that was not the answer the real answer is 1.7HZ