g/cm^3 * cm^3 * atoms/g = atoms
or,
g/cm^3 * cm^3 ÷ g/atom = atoms
2.70 * (pi * .25^2 * 10) / (4.48*10^-23) = 1.18 * 10^23
an aluminum cylinder is 10.0 cm in length and has a radius of .25 cm. if the mass of a single atom of aluminum is 4.48X10^-23 calculate the number of aluminum atoms present in the cylinder. the density of aluminum is 2.70 g/cm^3
Please answer quickly.
2 answers
An aluminum cylinder is 10.0 cm in length and has a radius of 0.25 cm.
If the mass of a single Al atom is 4.48 × 10−23g, calculate the number of
Al atoms present in the cylinder. The density of aluminum is 2.70 g/cm
If the mass of a single Al atom is 4.48 × 10−23g, calculate the number of
Al atoms present in the cylinder. The density of aluminum is 2.70 g/cm
2 answers