An alternative route to the production of propylene from propane would be
through oxydehydrogenation
At atmospheric pressure, what is the fraction of propane converted to propylene
at 400, 500, and 600°C if equilibrium is reached at each temperature? Compare
the results to those from Exercise 1. What do you think is the major impediment
to this route of olefin formation versus dehydrogenation? Assume ideal
behavior.
Temperature (0C)
400 ka :1.16* 10~26
500 Ka: 5.34 X 10~23
600 ka: 8.31 X 10~21