To analyze the given equation \( v(s) = 10(2^s) \), we can determine the domain and range of the function.
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Domain:
- The variable \( s \) represents the number of shares a video receives. Since it is not possible to have a negative number of shares, \( s \) must be greater than or equal to 0. Therefore, the domain of \( s \) is \( s \geq 0 \).
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Range:
- The function \( v(s) = 10(2^s) \) starts from 10 when \( s = 0 \) (because \( 2^0 = 1 \)). As the number of shares \( s \) increases, \( v(s) \) increases exponentially because \( 2^s \) grows very rapidly. Thus, the minimum value of \( v(s) \) is 10, and there is no upper limit as \( s \) can increase indefinitely. Therefore, the range of \( v(s) \) is \( v \geq 10 \).
Based on this analysis, the correct statement about the equation is:
The domain (s-values) includes the values (s ≥ 0).