just convert the vectors to x-y components, add them, and you have the resultant.
Can you get that far? If not, where do you get stuck?
An airplane’s velocity with respect to the air is 630 mph, and its heading is 𝑁 30° 𝐸. The wind, at the altitude of the plane, is directly from the southeast at 45° and has a velocity of 45 mph. Draw a figure that gives a visual representation of the situation. What is the true direction of the plane, and what is its speed with respect to the ground?
4 answers
I did get to that part, I drew the picture, but I think I kept using the wrong angles, I'm not really sure
630 @ 𝑁 30° 𝐸 = <315.00,545.58>
wind from the SE is in the direction NW, so 45 @ NW = <-31.82,31.82>
Now, if the plane's ground speed is <x,y> we have
<x,y> + <-31.82,31.82> = <315.00,545.58>
x = 346.82
y = 513.76
That translates into a speed of 619.87 in the direction (from the x-axis) of 55.98°. That makes a heading of 145.98°
wind from the SE is in the direction NW, so 45 @ NW = <-31.82,31.82>
Now, if the plane's ground speed is <x,y> we have
<x,y> + <-31.82,31.82> = <315.00,545.58>
x = 346.82
y = 513.76
That translates into a speed of 619.87 in the direction (from the x-axis) of 55.98°. That makes a heading of 145.98°
sorry; the heading is 34.02°
(It's 90-A), not 90+A
(It's 90-A), not 90+A
3 answers