Vo = 27.4m/s[48o]
Xo = 27.4*Cos48 = 18.3 m/s.
Yo = 27.4*sin48 = 20.4 m/s.
h = 0.5g*t^2 = 860 m.
4.9*t^2 = 860
t^2 = 175.5
Tf = 13.2 s. = Fall time.
Dx = Xo*Tf = 18.3m/s * 13.2s = 242.4 m.
b. Y = Yo + g*t = 0 + 9.8*13.2 = 129.4
m/s.
Tan A = Y/Xo = 129.4/18.3 = 7.07104
A = 82o.
An airplane with a speed of 27.4 m/s is climbing upward at an angle of 48° counterclockwise from the positive x axis. When the plane's altitude is 860 m the pilot releases a package.
(a) Calculate the distance along the ground, measured from a point directly beneath the point of release, to where the package hits the earth.
Determine the angle of the velocity vector of the package just before impact.
1 answer