an airplane was moving with a velocity equal to 300 mph when the velocity was increased with uniform acceleration to 600 mph in 5 min. calculate the number of miles the airplane traveled during that interval of time

Answer 1

Vo = 300mi/h * 1600m/mi * 1h/3600s =133.3 m/s.

Vf = (600/300) * 133.33 = 266.66 m/s.

t = 5min * 60s/min = 300 s.

a = (Vf-Vo)/t = (266.66-133.33) / 300 =
0.444 m/s^2.

d = Vo*t + 0.5a*t^2,
d = 133.33*300 + 0.222*(300)^2=59,979 m
= 37.5 mi.