An airplane traveling horizontally at 367 km/hr at a height of 1 km releases a bomb. How far ahead (to the nearest meter) from the release point does the bomb strike the ground?

Answer 1

time to fall 1000 m: d=1/2 g t^2
t=2d/g=2000/9.8 seconds

367km/hr=367/3.6 m/s

d=v*t=367/3.6 * 2000/9.8 meters