An airplane, traveling 142.5 km/hr at the moment it touches the runway, runs off the end of the runway still traveling at 36.7 km/hr. If the plane’s rate of deceleration was -1.6 m/s2, how long and how far did the plane travel along the runway?
2 answers
idek help me.
1 km/hr = 1000/3600 = 5/18 m/s
time taken to decelerate:
t = (142.5-36.7)(5/18)/1.6 = 18.368 s
In that time, it traveled
s = 142.5t - 0.8t^2 meters
time taken to decelerate:
t = (142.5-36.7)(5/18)/1.6 = 18.368 s
In that time, it traveled
s = 142.5t - 0.8t^2 meters
1 answer