an airplane is seen from an observation point on the ground at an angle of elevation of 37 degrees. it is seen from a second observation point on the ground 800 yards away from the first observation point at an angle of elevation of 65 degrees. how far is the airplane from the first observation point?

1 answer

Make a sketch
Label the position of the plane as P
label the point directly below P as Q
Label the first observation point A and the second observarion point as B
angle A = 37°
angle PBQ = 65°
AB = 800
You can easily see that angle APB= 28°
In triangle ABP you can find side ATP using the sine law.