An airplane is leaving the first airport (A) at a bearing of 70 degrees. It then travels 238 miles to airport B. After fueling up, it leaves at a bearing of 120 degrees and lands at airport C. After fueling up it finally returns to airport (A) at a bearing of 260 degrees. What is the total miles of the complete trip?

Put your answer to 1 decimal place into answerblank 1 (no spaces)

1 answer

change "bearing" to "heading" throughout.

Draw a diagram. Angle CAB = 60°, ABC = 90° and BCA = 30°

so, you have a 30-60-90 triangle, with the long leg=238.

short leg = 238/√3 = 137
and hypotenuse twice that or 274

so, the whole trip is 238+137+274=649 miles