The time it takes for the supplies to hit the ground can be calculated using the formula:
t = sqrt(2h / g)
where t is the time, h is the height (80m), and g is the acceleration due to gravity (9.81 m/s^2).
Plugging in the values:
t = sqrt(2 * 80 / 9.81) = 4 seconds
Therefore, the horizontal distance the airplane travels during this time can be calculated using the formula:
d = v * t
where d is the distance, v is the speed of the airplane (350 m/s), and t is the time we calculated (4 seconds).
Plugging in the values:
d = 350 * 4 = 1400 meters
So the horizontal distance from the target when the supplies are released is 1400 meters. However, the target is not directly below the airplane, but at an angle. Using trigonometry, we can calculate the actual horizontal distance from the target:
cos(theta) = adjacent / hypotenuse
cos(theta) = 80 / 1400
theta = arccos(80 / 1400)
theta ≈ 83.56 degrees
Therefore, the horizontal distance from the target when the supplies are released is:
1400 * cos(83.56) ≈ 393 meters
Hence, the answer is 393 meters.
An airplane is flying. level 80 m above the ground with a speed of 350m/s The bombarding wishes to drop supplies on a target ground at will horizontal distance from the target shut the person release the supplies the answer is 393
1 answer