h= gt²/2 =>
t=sqrt{2h/g},
s=vt
An airplane is flying horizontally 100m above the ground at 50.0 m/s. Ignoring air resistance, how far before the target should an object be dropped?
2 answers
H=125m u=25m/s so H=u²sin²theta/2g then we will get value of sintheta and put it in formula R=u²sin2theta/g then we will get answer.