The plane is at a distance d where
d^2 = 75^2+35^2+6^2 = 6886
d = 83 km (82.99, but who's checking?)
the angle of elevation θ = arctan(6/83) = 4.169° = 4°10'8"
an airplane is flying 75km south and 35 km west of an airport. It is flying at a heigh of 6 km
A)what is the straight-line distance to the airport?
B)What is the angle of elevation of the airplane, from the point of of view of the airport?
3 answers
oops.
θ = arcsin(6/83) = 4.145°
θ = arcsin(6/83) = 4.145°
θ = arcsin(6/83) = 4.145°
1 answer