upwind speed = u -w
downwind speed = u+w
1650 = (u-w)(3.3 hours)
1650 = (u+w)(3)
3 u + 3 w = 1650
3.3 u - 3.3 w = 1650
3.3 u + 3.3 w = 1.1*1650 = 1815
3.3 u - 3.3 w = 1650
-------------------- add
6.6 u = 3465
u = 525 miles/hour
now find w
An airplane flying into a headwind travels the 1650-mile flying distance between two cities in 3 hours and 18 minutes.
On the return flight, the distance is traveled in 3 hours.
Find the airspeed of the plane and the speed of the wind, assuming that both remain constant.
1 answer