An airplane flying at 390 mph has a bearing of N 28°W. After flying 3 hours, how far north and how far west has the plane traveled from its point of departure?

Answer 1

V = 390mi/h[28o]N of W.

D = 390mi/h[28o] * 3h = 1170 mi[28o]N. of W.

Dn = 1170*Cos28 =
Dw = 1170*sin28 =