An airplane flies at an airspeed of 445km/hr. The pilot wants to fly 785km to the north. She knows that she must head 18.0° east of north to fly directly there. If the plane arrives in 1.97hr, find the magnitude of the wind velocity vector.

Answer 1

the plane flies 445*1.97 = 876.65 km

So, in still air, its position would be

(270.9,833.7)

So, you want

Vx * 1.97 = 0-270.9
Vy * 1.97 = 785-833.7

Now you know Vx and Vy, so you can find V and its direction