An airplane flies 200 km due west from city A to city B and then 260 km in the direction of 32.0° north of west from city B to city C.

Question

(a) In straight-line distance, how far is city C from city A?
?km

(b) Relative to city A, in what direction is city C?
?° north of west

Answer 1

(a) Add up the x (east) and y (north) component displacement and then compute the magnitude of the resultant.
X = -200 - 260 cos 32
Y = 260 sin 32
distance = sqrt (X^2 + Y^2)

(b) The direction is in the second quadrant, since X is negative and Y is positive. If A is the angle north from west, A = arctan (-Y/X)

Answer 2

thank you for the help....but still could not figure out the answer

Answer 3

a) 484km
b) 18 degrees nw