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An airplane accelerates down a runway at 100 m/s2 for 15 s until it finally lifts off the ground. Determine the distance travel...Question
An airplane accelerates down a runway at 5.20 m/s2 for 32.8 s until it finally lifts off the ground. Determine the distance traveled before takeoff.
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Answered by
GPT 3.5
To determine the distance traveled before takeoff, we can use the kinematic equation:
d = vi * t + 0.5 * a * t^2
where:
d = distance traveled
vi = initial velocity (0 m/s since the airplane starts from rest)
a = acceleration (5.20 m/s2)
t = time (32.8 s)
Plugging in the values:
d = 0 * 32.8 + 0.5 * 5.20 * (32.8)^2
d = 0 + 0.5 * 5.20 * 1075.84
d = 0 + 0.5 * 5600.768
d = 2800.384
Therefore, the distance traveled before takeoff is 2800.384 meters.
d = vi * t + 0.5 * a * t^2
where:
d = distance traveled
vi = initial velocity (0 m/s since the airplane starts from rest)
a = acceleration (5.20 m/s2)
t = time (32.8 s)
Plugging in the values:
d = 0 * 32.8 + 0.5 * 5.20 * (32.8)^2
d = 0 + 0.5 * 5.20 * 1075.84
d = 0 + 0.5 * 5600.768
d = 2800.384
Therefore, the distance traveled before takeoff is 2800.384 meters.
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