an airplance traveling at 450 km/h needs to reverse its course. the pilot decides to bank the wings at 12 degrees. find the time needed to reverse the course

Answer 1

force in = mg sin 12 = m v^2/r

v^2/r = g sin 12

turns 180 deg = pi radians

r = v^2/(g sin 12)
pi r = distance flown = pi v^2/(g sin 12)

time = distance / speed = pi r/v
= pi v/(g sin 12
here v = 450/3.6 and g = 9.81