An aircraft maintains a speed of 500 miles per hour in a southwestern direction. The velocity of the jet stream is constant 50 miles per hour from the west. Find the resultant vector, the speed, and actual direction of the aircraft.

Answer 1

R = 500mi/h @ 225o + 50mi/h @ 0o

X = 500*cos225 + 50 = --303.6/303.6 mi/h.
Y = 500*sin225 = -353.6 mi/h.

tanAr = Y/X = -353.6/-303.6 = 49.35o =
Reference Angle.
A = 49.35 + 180 = 229.35o,CCW = 40.65o
West of South = Direction.

V = X/cosA = -303.6/cos229.35=466 mi/h.