An aircraft flew 3hrs with the wind. The return trip took 4hrs against the wind. If the speed of the plane in still air is 180mph more than the speed of the wind, find the wind speed and the speed of the plane in still air.

Answer 1

distance=rate*time
d=rt

wind speed=w
plane spee=180+w

d=[(180+w)+w]*3 With wind
d=[(180+w)-w]*4 Against wind
[(180+w)+w]*3=[(180+w)-w)*4

(180+2w)3=180*4
540+6w=720
6w=180
w=30

The wind speed is 30 mph.

The plane in still air is 180+30, or 210.