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An air-track cart with mass m1=0.29kg and initial speed v0=0.95m/s collides with and sticks to a second cart that is at rest initially.
Part A
If the mass of the second cart is m2=0.55kg, how much kinetic energy is lost as a result of the collision?
4 answers
An air-track cart with mass m1=0.29kg and initial speed v0=0.95m/s collides with and sticks to a second cart that is at rest initially.
Part A
If the mass of the second cart is m2=0.55kg, how much kinetic energy is lost as a result of the collision?
Part A
If the mass of the second cart is m2=0.55kg, how much kinetic energy is lost as a result of the collision?
Initial KE = 0.5*0.29*0.95^2
= 0.1308625
Final KE= (0.5*0.29*0.95^2)-(0.5*(0.29+0.55)*((0.29*0.95)/(0.29+0.55))^2)
= 0.0451787
lost in the collision= Final KE - Initial KE
= 0.0451787-0.1308625
= -0.08568 J -------> Answer
= 0.1308625
Final KE= (0.5*0.29*0.95^2)-(0.5*(0.29+0.55)*((0.29*0.95)/(0.29+0.55))^2)
= 0.0451787
lost in the collision= Final KE - Initial KE
= 0.0451787-0.1308625
= -0.08568 J -------> Answer
Still need answer, above one is wrong