Hmmm.
a. Electric Field= potentialDifference/distance
b. C=epsilion*area/distance=q/V
q/area=epsilion*Voltage/distance
c. see b. solve for C
d. solve for q.
An air-filled capacitor consists of two parallel plates, each with an area of 7.60 cm2, separated by a distance of 1.70 mm.
(a) If a 16.0 V potential difference is applied to these plates, calculate the electric field between the plates.
kV/m
(b) What is the surface charge density?
nC/m2
(c) What is the capacitance?
pF
(d) Find the charge on each plate.
pC
1 answer
1 answer