An air bubble of volume 15 cc is formed at a depth of 50 m in a lake. If the temperature of the bubble while rising remains constant then what will be the volume of the bubble at the surface?(Given: g=10 m/s2 & atm. pressure = 1.0 * 100000 Pa)

Answer 1

p1•V1 = p2•V2,
ρ•g•h• V1 = p2•V2,
V2 = ρ•g•h• V1/ p2,
ρ = 1000 kg/m^3 is the density of water,
p is the atm. pressure

Answer 2

i am not getting the answer which is 90cc

Answer 3

take p1= ro*g*h + p atmospheric
then u will get it:

(10^3*10*50+10^5)15=10^5*v
v=90cc

njoy...:)