An aeroplane takes off from runway making an angle of 30 horizontally at a speed 500ms find the height attained by the aeroplane after 15s?

Answer 1

h/(500*15) = 1/2

Review the properties of a 30-60-90 right triangle.

Answer 2

200

Answer 3

Vertical velocity (component) of the plane= 500sin30° m/s= 250 m/s.
H= ut (REMEMBER! IT IS NOT A PROJECTILE! IT IS A PLANE AND IT WILL MOST PROBABLY RISE WITH THE SAME SPEED IN THIS SCENARIO!).
H= ut
H= 250*15
H= 3750m. (Height attained by it after 15s).