An aeroplane leave Bibiani at 10:10pm and reaches Accra 4415km away at 5:50am the next morning. Find correct to the nearest whole number the average speed of the aeroplane in km/h.

Answer 1

10:10 PM to 5:10 AM is 7 hours, so the time is 7hr 40 min = 23/3 hours
speed = distance/time, so
4415km / (23/3 hr) = 575.87 km/hr

Answer 2

solving steps

Answer 3

step by step

Answer 4

575.87km/hr