An aeroplane flies due north from airport P to Q and then flies due east R. If Q is equidistant from P and R, find the bearing of P and R

Question

A. 90o
B. 135o
C. 225o
D. 270o

Answer 1

The bearing is the angle measured clockwise from the north direction.

Since the airplane flies due north from P to Q, the bearing of P is 0 degrees.

Since Q is equidistant from P and R, the triangle PQR is an isosceles right triangle.

Therefore, the bearing of R is 90 degrees more than the bearing of Q.

Since the airplane flies due east from Q to R, the bearing of R is 90 degrees.

Thus, the bearing of P is 0 degrees and the bearing of R is 90 degrees.

Therefore, the correct answer is D. 270o.