An advertising company orders a poster that is 342 square feet. If its length is 1 foot greater than its width, find the dimensions of the poster.

Answer 1

L(L-1)=342
L^2-L-342=0
(L-19)(L+18)=0

L=19, w=18

Answer 2

The area of a rectangular plot is 136 square meters. The length of the plot (in meters) is one more than twice its width. Find the length and width of the plot.

Answer 3

Let's call the width of the plot "x".

Then we know that:

- The length is one more than twice the width, so it is: 2x + 1

We also know that the area of a rectangle is found by multiplying the length by the width, so:

- (length)(width) = 136

Now we can substitute the expression we found for the length:

- (2x + 1)(x) = 136

Expanding the brackets:

- 2x^2 + x = 136

Bringing everything to one side:

- 2x^2 + x - 136 = 0

This equation doesn't factor nicely, so we'll use the quadratic formula:

- x = (-1 ± sqrt(1 + 4(2)(136))) / (2(2))

- x ≈ 7.68 or x ≈ -8.93

We can ignore the negative solution (width can't be negative), so we have:

- x ≈ 7.68

Now we can find the length using 2x + 1:

- length = 2(7.68) + 1

- length ≈ 15.36 + 1

- length ≈ 16.36

So the width is approximately 7.68 meters and the length is approximately 16.36 meters.