Ke initial = (1/2)(91)(2.7)^2 = 332 Joules
Ke final = (1/2)(91)(1.02)^2 = 47.3 Joules
332 J - 615 J + 3620 J = 47.3 J + m g h
so
m g h = 3290 Joules
h = 3290/ (91*9.81) = 3.69 meters
(how did the ice get tilted ? :)
An 91.0 kg in-line skater does 3620 J of nonconservative work by pushing against the ground with his skates. In addition, friction does -615 J of nonconservative work on the skater. The skater's initial and final speeds are 2.70 m/s and 1.02 m/s, respectively.
Part B
Calculate the change in height of the skater.
1 answer
1 answer