An 800-kg car traveling in a straight line at a speed of 30 m/s applies its brakes. During braking, there is a net force of 2000 N in the horizontal direction on the car. What distance will the car move from the time it applies its brakes until it has stopped?

Answer 1

a = Fn/m = 2000 / 800 =- 2.5 m/s^2.

d = (Vf^2-Vo^2)/2a,
d = (0-(30)^2 / -5 = 180 m.