An 80-kg hiker climbs to the top of a tall hill and builds up 470,000 J of gravitational potential energy. How high did the hiker climb? Round the answer to the nearest hundred

1 answer

To find the height the hiker climbed, we can use the formula for gravitational potential energy:

\[ PE = mgh \]

where:

  • \( PE \) is the potential energy (in joules),
  • \( m \) is the mass (in kilograms),
  • \( g \) is the acceleration due to gravity (approximately \( 9.81 , \text{m/s}^2 \)),
  • \( h \) is the height (in meters).

Rearranging the formula to solve for height \( h \),

\[ h = \frac{PE}{mg} \]

Given:

  • \( PE = 470,000 , \text{J} \)
  • \( m = 80 , \text{kg} \)
  • \( g = 9.81 , \text{m/s}^2 \)

Substituting the values into the equation:

\[ h = \frac{470,000 , \text{J}}{80 , \text{kg} \times 9.81 , \text{m/s}^2} \]

Calculating the denominator:

\[ 80 , \text{kg} \times 9.81 , \text{m/s}^2 = 784.8 , \text{kg m/s}^2 \]

Now substituting back:

\[ h = \frac{470,000 , \text{J}}{784.8 , \text{kg m/s}^2} \approx 599.19 , \text{m} \]

Rounding to the nearest hundred:

\[ h \approx 600 , \text{m} \]

So, the height the hiker climbed is approximately 600 meters.