An 8.5 x 10^2 elevator is pulled up at a constant velocity of 1 m/s by a 10 kW motor. Calculate the efficiency of the motor.

Answer 1

power in work= mgh/t=8.5E2*9.8*1m/s=about 5000 watts

Efficiencey appx= 5000/10K aboaut 50 percent.

check that.

Answer 2

You have to provide dimensions along with the 850 for the elevator.

M g V is the power delivered.

Divide that by 10,000 W for the efficiency

Answer 3

Ok thanks to both for the answers!