To find the total area covered by the two circles, we first find the area of each individual circle.
The first circle has a diameter of 4 inches, so its radius is half of the diameter, which is 4/2 = 2 inches. The area of this circle is given by the formula A = πr^2, where A is the area and r is the radius. Substituting the value of the radius, we have A1 = π(2^2) = 4π square inches.
The second circle has a diameter equal to the arc AB, which has a length of 4 inches. Since the arc is a quarter-circle, the diameter is the same as the radius of a full circle. Hence, the radius of the second circle is also 4 inches. The area of this circle is A2 = π(4^2) = 16π square inches.
The total area covered by the two circles is the sum of their individual areas. So, the total area is A1 + A2 = 4π + 16π = 20π square inches.
Here is a visual representation of the two circles:
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The small circle corresponds to the first circle, and the larger circle corresponds to the second circle. The two circles overlap such that AB is the diameter of both circles.
Amy marks two points A and B that are 4 inches apart. She draws one circle that has segment AB as a diameter. She then draws a larger circle, which overlaps the first circle, such that the arc from A to B along its circumference is a quarter-circle. What is the total area covered by the two circles? Express your answer in terms of pi. Could you draw a visual picture of this.?
1 answer