Amy invests $10000 in an account that compounds annually at a rate of 11%. After 10 years, how much is in the account?

• $28.394.21
• $31,504.11
O $41.117.12
O $41,678.92

1 answer

To calculate the future value of an investment compounded annually, you can use the formula:

\[ A = P(1 + r)^n \]

Where:

  • \( A \) is the amount of money accumulated after n years, including interest.
  • \( P \) is the principal amount (the initial amount of money).
  • \( r \) is the annual interest rate (decimal).
  • \( n \) is the number of years the money is invested or borrowed.

For this scenario:

  • \( P = 10000 \)
  • \( r = 11% = 0.11 \)
  • \( n = 10 \)

Now, plug these values into the formula:

\[ A = 10000(1 + 0.11)^{10} \] \[ A = 10000(1.11)^{10} \]

Calculating \( (1.11)^{10} \):

\[ (1.11)^{10} \approx 2.83942 \]

Now, multiply by 10,000:

\[ A \approx 10000 \times 2.83942 \approx 28394.21 \]

So, after 10 years, the amount in the account is approximately $28,394.21.

Therefore, the correct answer is:

• $28,394.21