To determine which equation is in a balanced state, we need to verify that the same number of each type of atom appears on both sides of the equation.
Let's analyze each option:
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C3H8 + 11 O2 → 3 CO2 + 8 H2O
- Left Side: C: 3, H: 8, O: 22 (11 O2)
- Right Side: C: 3, H: 16 (from 8 H2O), O: 22 (6 from CO2 and 8 from H2O)
- Not balanced (H atoms are unbalanced).
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2 C3H8 + 4 O2 → 2 CO2 + 4 H2O
- Left Side: C: 6, H: 16, O: 8 (4 O2)
- Right Side: C: 6 (from 2 CO2), H: 8 (from 4 H2O), O: 8 (2 from CO2 and 4 from H2O)
- Not balanced (H atoms are unbalanced).
-
C3H8 + 3 O2 → CO2 + H2O
- Left Side: C: 3, H: 8, O: 6 (3 O2)
- Right Side: C: 1 (from CO2), H: 2 (from H2O), O: 3 (1 from CO2 and 1 from H2O)
- Not balanced (C and H atoms are unbalanced).
-
C3H8 + 5 O2 → 3 CO2 + 4 H2O
- Left Side: C: 3, H: 8, O: 10 (5 O2)
- Right Side: C: 3 (from 3 CO2), H: 8 (from 4 H2O), O: 10 (6 from CO2 and 4 from H2O)
- This equation is balanced.
Thus, the correct answer is:
C3H8 + 5 O2 → 3 CO2 + 4 H2O (this equation is in a balanced state).