Look at the order of filling. That is
1s, 2s, 2p, 3s, 3p, 4s, 3d etc.
So if n = 3 and l = 2, the electrons must be a 3d electron. For n = 4 and l = 0, that's a 4s electron. The 4s is lower energy than the 3d. I think B.
Among the following electrons, which has highest energy? a. n = 3, l = 2, m = 0, s = + 1/2 b. n = 4, l = 0. m= 0 , s = - 1/2
Ans is A... but how A? Why nOt B?
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