Ammonium carbonate decomposes upon heating according to the following balanced equation:

Question

(NH4)2CO3(s)→2NH3(g)+CO2(g)+H2O(g)

Calculate the total volume of gas produced at 24.0∘C and 1.02atm by the complete decomposition of 11.9g of ammonium carbonate.

Please show steps on how you got the answer. Thank you!

Answer 1

11.9g of am carb = 11.9/96.1 = 0.124 moles

So, you get
0.248 moles of NH3
0.124 moles CO2
0.124 moles H2O
Total moles of gas: 0.496

So, since 1 mole makes 22.4L at STP, adjust for your conditions.

Answer 2

If you have trouble adjusting for the conditions you can use PV = nRT. Plug in n from Steve's work, along with the other conditions, and solve for V in L. Same answer either way but I think this way is a little easier for students.