q = mass x heat vaporization = ??
Convert 355 g NH3 to mols and plug in for mass. heat of vaporization is in kJ/mol. The answer will be in kJ. Note the correct spelling of Celsius.
Ammonia, NH3, is used as a refrigerant. At its boiling point of -33 degress Celcius, the enthalpy of vaporization of ammonia is 23.3 kJ/mol. How much heat is required to vaporize 355 g of ammonia at -33 degrees Celcius?
a. 1.12 kJ
b. 152 kJ
c. 251 kJ
d. 486 kJ
e. 8.27 x 10^3 kJ
3 answers
thx
i thought is was D