ammonia is produced from the reaction of nitrogen and hydrogen according to the following balanced equation.

N2+3H2g----- > 2NH3g.
what is the maximum mass that can be produced from a mixture of 2.00×10³gN and 8.00×10⁴H2?

2 answers

I assume you mean maximum mass NH3 and I assume 8.00E4 g H2.

This is a limiting reagent problem (LR).
N2(g) + 3H2(g)----- > 2NH3(g).

1a. Convert g N2 to mols. mols = g/molar mass = ?
1b. Convert g H2 to mols the same way.
2a. Using the coefficients in the balanced equation, convert mols N2 to mols NH3. That will be mols N2 from 1a x (2 mol NH3/1 mol N2) = mols NH3 produced.
2b. Do the same and convert mols H2 to molsNH3 produced.
2c. It is likely that 2a and 2b will not be the same. If they are different, in LR problems the SMALLER number will be the correct answer for mols.
3a. Using the smaller number from 2c, convert mols NH3 to grams NH3. grams = mols x molar mass = ?
2.0468×10^73g