CO2(g) + 2 NH3(g) --> CO(NH2)2 (s) + H2O(g).
mols CO2 = grams/molar mass = ?
mols NH3 = 4.50 L x (1 mol/22.4L) = ?
Convert mols CO2 to mols urea produced = 1:1 or mols NH3 = mols urea.
Convert mols NH3 to mols urea produced = 2 mol NH3 = 1 mol urea
In limiting reagent problems (LR) the mols product formed is the SMALLER of the two possibilities. The eagent producing the smaller number of mols or product is the LR.
Post your work if you get stuck.
Ammonia is not the only possible fertilizer. Others include urea, which can be produced by the reaction, CO2(g) + 2 NH3(g) --> CO(NH2)2 (s) + H2O(g).
A scientist has 75g of dry ice to provide the carbon dioxide. If 4.50L of ammonia at 15C and a pressure of 1.4atm is added, which reactant is limiting? What mass of urea will form?
2 answers
where did 22.4 L come from? and how do I get the mass?
1 answer