To analyze the reaction where nitrogen gas (\( \text{N}_2 \)) reacts with hydrogen gas (\( \text{H}_2 \)) to form ammonia (\( \text{NH}_3 \)), let’s first look at the balanced chemical equation:
\[ \text{N}_2 + 3\text{H}_2 \rightarrow 2\text{NH}_3 \]
From this balanced equation, we can determine the number of atoms in the reactants and products.
Reactants:
-
Nitrogen (\( \text{N}_2 \)):
1 molecule of \( \text{N}_2 \) contains 2 nitrogen atoms.
Total nitrogen atoms in reactants: 2 -
Hydrogen (\( \text{H}_2 \)):
3 molecules of \( \text{H}_2 \) contain 3 × 2 = 6 hydrogen atoms.
Total hydrogen atoms in reactants: 6
Summary of Reactants:
- Number of atoms in reactants:
- N: 2
- H: 6
Products:
According to the balanced equation, 2 molecules of ammonia (\( \text{NH}_3 \)) are produced:
- Each molecule of \( \text{NH}_3 \) contains 1 nitrogen atom and 3 hydrogen atoms.
- Therefore, for 2 molecules of \( \text{NH}_3 \):
- Total nitrogen atoms = 2 × 1 = 2
- Total hydrogen atoms = 2 × 3 = 6
Summary of Products:
- Number of atoms in products:
- N: 2
- H: 6
Final Summary:
| Chemical element | Number of atoms in reactants | Number of atoms in products | |------------------|------------------------------|------------------------------| | H | 6 | 6 | | N | 2 | 2 |
Thus, the numbers of each type of atom are conserved in the reaction, which aligns with the law of conservation of mass.