Let's denote the 5-digit number as \( ABCDE \), where:
- \( A \) is the ten thousands place,
- \( B \) is the thousands place,
- \( C \) is the hundreds place (which is given as \( 7 \)),
- \( D \) is the tens place,
- \( E \) is the ones place.
From the problem, we have the following information:
- \( C = 7 \).
- \( B \) (the thousands place) is the greatest possible digit, so we will consider \( B = 9 \) initially.
- The ones place \( E \) is double the ten thousands place \( A \): \( E = 2A \).
- The digits \( B \) and \( E \) add up to 17: \( B + E = 17 \).
- The digits in the tens and ten thousands place add up to the digit in the hundreds place: \( D + A = C = 7 \).
Now let's analyze these conditions step by step.
Step 1: Start with \( B = 9 \).
When \( B = 9 \): \[ 9 + E = 17 \implies E = 17 - 9 = 8. \]
Step 2: Substitute \( E \) to find \( A \).
Now, from the condition \( E = 2A \): \[ 8 = 2A \implies A = \frac{8}{2} = 4. \]
Step 3: Find \( D \).
Using the equation \( D + A = 7 \): \[ D + 4 = 7 \implies D = 3. \]
Summary of Digits:
Now we have the digits:
- \( A = 4 \),
- \( B = 9 \),
- \( C = 7 \),
- \( D = 3 \),
- \( E = 8 \).
Thus, the number Amanda is thinking of is: \[ 49738. \]
Verification:
- The digit in the hundreds place is \( 7 \). (Correct)
- The digit in the thousands place is \( 9 \), the greatest possible digit. (Correct)
- The digit in the ones place \( 8 \) is double the digit in the ten thousands place \( 4 \). (Correct)
- The digits in the thousands place and ones place \( 9 + 8 = 17 \). (Correct)
- The digits in the tens and ten thousands place \( 3 + 4 = 7 \). (Correct)
All conditions are satisfied, hence the number Amanda is thinking of is:
\[ \boxed{49738}. \]