Akua now --- x
Ama now ---- 4x
Akua in 10 years ---- x+10
Ama in 10 years ---- 4x+10
4x+10 = 2(x+10)
solve for x
Ama is four times as old as Akua. In ten years time, Ama will be twice as old as Akua. What is their ages.
8 answers
let Ama's age be X and Akua's age be Y
first sentence
X=4Y.......(i)
second sentence
X+10=(Y+10)2......(ii)
substitute (i) into (ii)
4Y+10=2Y+20
collect like terms
4Y-2Y=20-10
2Y=10 divide both side by 2
2Y/2=10/2
Y=5
substitute Y into (i)
X=4*5
X=20
therefore Ama =20years and Akua=5years
first sentence
X=4Y.......(i)
second sentence
X+10=(Y+10)2......(ii)
substitute (i) into (ii)
4Y+10=2Y+20
collect like terms
4Y-2Y=20-10
2Y=10 divide both side by 2
2Y/2=10/2
Y=5
substitute Y into (i)
X=4*5
X=20
therefore Ama =20years and Akua=5years
Fantastic!!!
Ama is 4time as old as Akua. In 10year time Ama will twice as old as Akua find their ages
Thanks for your help and support
Let Ama age be X and Akua age be 4x
X =4x
4x +10=2(X+10)
4x+10 =2x+20
4x2x=20-10
2x =10
2 2
X=5
X =4x
4x +10=2(X+10)
4x+10 =2x+20
4x2x=20-10
2x =10
2 2
X=5
Akua now --- x
Ama now ---- 4x
Akua in 10 years ---- x+10
Ama in 10 years ---- 4x+10
4x+10 = 2(x+10)
solve for x
let Ama's age be X and Akua's age be Y
first sentence
X=4Y.......(i)
second sentence
X+10=(Y+10)2......(ii)
substitute (i) into (ii)
4Y+10=2Y+20
collect like terms
4Y-2Y=20-10
2Y=10 divide both side by 2
2Y/2=10/2
Y=5
substitute Y into (i)
X=4*5
X=20
therefore Ama =20years and Akua=5years
Ama now ---- 4x
Akua in 10 years ---- x+10
Ama in 10 years ---- 4x+10
4x+10 = 2(x+10)
solve for x
let Ama's age be X and Akua's age be Y
first sentence
X=4Y.......(i)
second sentence
X+10=(Y+10)2......(ii)
substitute (i) into (ii)
4Y+10=2Y+20
collect like terms
4Y-2Y=20-10
2Y=10 divide both side by 2
2Y/2=10/2
Y=5
substitute Y into (i)
X=4*5
X=20
therefore Ama =20years and Akua=5years
Yes, that's correct!